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arXiv:2611.11080 · v1

Two barriers for minimal time firing squads, with applications to four and five states

首次提交 2026-11-08 10:41
版本更新 2026-11-08 10:41
雷达观测 2026-11-10 12:16
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摘要

A minimal-time solution of the firing squad synchronization problem synchronizes every line of n cells at time 2n minus 2. Six states suffice; whether five do has been open since 1987. Every line agrees with the half line until its right ends echo returns. For minimal time solutions with any number of states, we prove that cells at distance j behind the half lines front become time-periodic only after time (1.5 minus epsilon)j, for every epsilon greater than 0 and infinitely many j, and that the half line is never periodic in time and space on a wedge at its left border, hence not eventually regular in our sense. With certified satisfiability checks, we exclude four states using the lines of lengths 2 to 5 and parts of the next five, and show that every five state minimal time solution uses at least 15 non quiescent neighbourhoods on its half lines first 78 anti-diagonals. We give five state rules synchronizing exactly the lengths 2 to 14.

作者备注:34 pages, 18 figures, accepted (awaiting print) at the Journal of Cellular Automata

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v1 · 2026-11-08 10:41 · 最新观测版本

Two barriers for minimal time firing squads, with applications to four and five states

A minimal-time solution of the firing squad synchronization problem synchronizes every line of n cells at time 2n minus 2. Six states suffice; whether five do has been open since 1987. Every line agrees with the half line until its right ends echo returns. For minimal time solutions with any number of states, we prove that cells at distance j behind the half lines front become time-periodic only after time (1.5 minus epsilon)j, for every epsilon greater than 0 and infinitely many j, and that the half line is never periodic in time and space on a wedge at its left border, hence not eventually regular in our sense. With certified satisfiability checks, we exclude four states using the lines of lengths 2 to 5 and parts of the next five, and show that every five state minimal time solution uses at least 15 non quiescent neighbourhoods on its half lines first 78 anti-diagonals. We give five state rules synchronizing exactly the lengths 2 to 14.

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